Which of the following is correctly matched?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. For $[Cu(NH_3)_4]^{2+}$,$Cu^{2+}$ is $3d^9$. It undergoes $dsp^2$ hybridization and is paramagnetic due to one unpaired electron.$2$. For $K_

Vedclass · Accepted Answer

$K_2[Ni(CN)_4]$: $dsp^2$,diamagnetic

Vedclass · Answer

(B) $1$. For $[Cu(NH_3)_4]^{2+}$,$Cu^{2+}$ is $3d^9$. It undergoes $dsp^2$ hybridization and is paramagnetic due to one unpaired electron.$2$. For $K_2[Ni(CN)_4]$,$Ni^{2+}$ is $3d^8$. $CN^-$ is a strong field ligand,causing pairing of electrons. It undergoes $dsp^2$ hybridization and is diamagnetic.$3$. $[Co(NH_3)_4(H_2O)_2]Cl_3$ involves $Co^{3+}$ $(3d^6)$. With weak field ligands,it undergoes $sp^3d^2$ hybridization and is paramagnetic.$4$. $[Pt(NH_3)_2Cl_2]$ is a square planar complex ($dsp^2$ hybridization) and is diamagnetic.Therefore,option $B$ is correctly matched.

List-$I$	List-$II$
$A. Ni(CO)_4$	$I. sp^3$
$B. [Ni(CN)_4]^{2-}$	$II. sp^3d^2$
$C. [Co(CN)_6]^{3-}$	$III. d^2sp^3$
$D. [CoF_6]^{3-}$	$IV. dsp^2$

Similar Questions

What is true for $[Fe(CN)_6]^{3-}$ and $[FeF_6]^{3-}$?

Match List-$I$ with List-$II$.

List-$I$ List-$II$

$A. Ni(CO)_4$ $I. sp^3$

$B. [Ni(CN)_4]^{2-}$ $II. sp^3d^2$

$C. [Co(CN)_6]^{3-}$ $III. d^2sp^3$

$D. [CoF_6]^{3-}$ $IV. dsp^2$

Choose the correct answer from the options given below.

The hybridization involved in the complex $[Ni(CN)_4]^{2-}$ is (Atomic number of $Ni = 28$):

The number of unpaired electrons in $[Co(NH_3)_6]^{3+}$ and $[CoF_6]^{3-}$ are respectively.....

What is the shape of $Fe(CO)_5$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module